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		<title>Sa beneficialmacheer Kalvi 1dosth Biochemistry Ionic Equilibrium Several More Inquiries</title>
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					<description><![CDATA[Sa beneficialmacheer Kalvi 1dosth Biochemistry Ionic Equilibrium Several More Inquiries Question 6. 1M CHstep step threeCOOH solution. The dissociation constant of acetic acid is 1.8 x 10 -5 . Answer: pH = – log[H + ] For weak acids, Question 7. Find the pH of a buffer solution containing 0.20 mole per litre sodium acetate [&#8230;]]]></description>
										<content:encoded><![CDATA[<p><title>Sa beneficialmacheer Kalvi 1dosth Biochemistry Ionic Equilibrium Several More Inquiries</title></p>
<p>Question 6. 1M CH<sub>step step three</sub>COOH solution. The dissociation constant of acetic acid is 1.8 x 10 -5 . Answer: pH = – log[H + ] For weak acids,</p>
<p>Question 7. Find the pH of a buffer solution containing 0.20 mole per litre sodium acetate and 0.18 mole per litre acetic acid. K<sub>a</sub> for acetic acid is 1.8 x 10 -5</p>
<p>Given that K<sub>a</sub> = 1.8 x 10 -5 pK<sub>a</sub> = – log (1.8 x 10 -5 ) = 5 – log 1.8 = 5 – 0.26 = cuatro.74 pH = 4.74 + log \(\frac < 0.20>< 0.18>\) = 4.74 + log \(\frac < 10>< 9>\) = 4.74 + log 10 – log 9 = 4.74 + 1 – 0.95 = 5.74 – 0.95 = 4.79</p>
<p>Concern 8. What is the pH out-of an aqueous provider acquired of the combination six gram of acetic acid and 8.2 gram out of sodium acetate and you can putting some regularity comparable to five hundred ml. (Given: K to own acetic acid are 8 x ten) Answer: Centered on Henderson – Hessalbalch picture,</p>
<ul>
<li>the newest hydrolysis ongoing,</li>
<li>degree of hydrolysis and you may</li>
<li>pH of O.1 M CH3COONa solution (pK<sub>a</sub> for CH<sub>3</sub>COOH is 4.74).</li>
</ul>
<p><sub>3</sub>COONa is a salt of weak acid (CH<sub>3</sub>COOH) and a strong base (NaOH). Hence, the solutions is alkaline due to hydrolysis. CH<sub>3</sub>COO (aq) + H<sub>2</sub>O (aq) \(\rightleftharpoons\) CH<sub>3</sub>COOH (aq) + OH – (aq) Give that pK<sub>a</sub> = 4.74 pK<sub>a</sub> = – log K<sub>a</sub> i.e., K<sub>a</sub> = antilog of ( – PK<sub>a</sub>) = antilog of ( – 4.74) = antilog of( – 5 + 0.26) 10 -5 x 1.8</p>
<ol>
<li>BaSO<sub>4</sub></li>
<li>Ag<sub>2</sub>(CrO<sub>4</sub>)</li>
</ol>
<h2>Calculate new pH out of 0</h2>
<p>Question 1. Which one of the following buffer is present in blood? (a) CH<sub>3</sub>COOH + CH<sub>3</sub>COONa (b) NH<sub>4</sub>OH + NH<sub>4</sub>Cl (c) H<sub>2</sub>CO<sub>3</sub> + NaHCO<sub>3</sub> (d) HCI + NaCl Answer: (c) H<sub>2</sub>CO<sub>3</sub> + NaHCO<sub>3</sub></p>
<p><span id="more-18776"></span></p>
<p>Matter dos. And this of one&#8217;s adopting the is usually included in the newest manure community? (a) Lactic acid (b) Sulphuric acid (c) Tannic acidic (d) Carbonic-acid Address: (b) Sulphuric acidic</p>
<h2>Answer: CH</h2>
<p>Question 3. Which of the following is present in an antacid tablet? (a) NaOH (b) Mg(OH)<sub>2</sub> (c) Al(OH)<sub>3</sub> (d) either (b) or (c) Answer: (d) either (b) or (c)</p>
<p>Concern 4. This new acidic within whole milk was &#8230;&#8230;&#8230;&#8230;.. (a) Lactic acid (b) Tannic acid (c) Tartaric acidic (a) Acetic acid Answer: (a) Lactic acidic</p>
<p>Concern 5. Think about the after the comments. (i) Acid needs bitter (ii) Acidic converts red litmus so you can blue (iii) Acid responds which have metals and you will liberates hydrogen gas</p>
<p>Hence of your own a lot more than statement was We are proper? (a) (i) merely (b) (i) (ii) (c) (i) (iii) (d) (ii) simply Address: <a href="https://datingranking.net/escort-directory/los-angeles/">https://datingranking.net/escort-directory/los-angeles/</a> (c) (i) (iii)</p>
<p>Concern six. Take into account the following statements. (i) Acid choices bitter. (ii) Acid converts bluish litmus so you can purple (iii) Acid is likely to accept a good proton off their ingredients.</p>
<p>And this of your own over report was We commonly right? (a) (i) (ii) (b) (ii) (iii) (c) (iii) merely (a) (ii) simply Answer: (c) (iii) just</p>
<p>Question 7. Which of the following can act as an acid as well as a base by Lowry – Bronsted theory? (a) H<sub>2</sub>O (b) NH<sub>3</sub> (c) NH<sub>4</sub>OH (d) Ca(OH)<sub>2</sub> Answer: (a) H<sub>2</sub>O</p>
<p>Question 8. In the reaction HCI + H<sub>2</sub>O \(\rightleftharpoons\) H<sub>3</sub>O + Cl – which one of the acid-base pair? (a) HCl + H<sub>3</sub>O + (b) HCI + CI – (c) H<sub>3</sub>O + Cl (d) H<sub>2</sub>O + Cl – Answer: (b) HCI + CI –</p>
<p>Question 9. Which of the following is considered Lewis acid? (a) NH<sub>3</sub> (b) BF<sub>3</sub> (c) HF (d) HCl Answer: (b) BF<sub>3</sub></p>
<p>Question 10. Which of the following is considered as Lewis base? (a) BF<sub>3</sub> (b) AICI<sub>3</sub> (c) HCI (d) NH<sub>3</sub> Answer: (d) NH<sub>3</sub></p>
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